2[y+1]+4y=3[2y-1]+8

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Solution for 2[y+1]+4y=3[2y-1]+8 equation: 


Simplifying
2[y + 1] + 4y = 3[2y + -1] + 8

Reorder the terms:
2[1 + y] + 4y = 3[2y + -1] + 8
[1 * 2 + y * 2] + 4y = 3[2y + -1] + 8
[2 + 2y] + 4y = 3[2y + -1] + 8

Combine like terms: 2y + 4y = 6y
2 + 6y = 3[2y + -1] + 8

Reorder the terms:
2 + 6y = 3[-1 + 2y] + 8
2 + 6y = [-1 * 3 + 2y * 3] + 8
2 + 6y = [-3 + 6y] + 8

Reorder the terms:
2 + 6y = -3 + 8 + 6y

Combine like terms: -3 + 8 = 5
2 + 6y = 5 + 6y

Add '-6y' to each side of the equation.
2 + 6y + -6y = 5 + 6y + -6y

Combine like terms: 6y + -6y = 0
2 + 0 = 5 + 6y + -6y
2 = 5 + 6y + -6y

Combine like terms: 6y + -6y = 0
2 = 5 + 0
2 = 5

Solving
2 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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